Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
Azken | 554 | 39 | 1 | 39.0000 |
Beste | 668 | 38 | 1 | 38.0000 |
Horren | 675 | 23 | 1 | 23.0000 |
Hona | 509 | 22 | 1 | 22.0000 |
baina | 2739 | 99 | 5 | 19.8000 |
Esan | 219 | 15 | 1 | 15.0000 |
Ezin | 154 | 13 | 1 | 13.0000 |
Hala | 963 | 13 | 1 | 13.0000 |
Zeren | 238 | 12 | 1 | 12.0000 |
Horrek | 339 | 12 | 1 | 12.0000 |
Ganbarak | 124 | 12 | 1 | 12.0000 |
proposatu | 104 | 12 | 1 | 12.0000 |
Hau | 361 | 11 | 1 | 11.0000 |
Hori | 1010 | 22 | 2 | 11.0000 |
Bide | 108 | 10 | 1 | 10.0000 |
Helburu | 102 | 10 | 1 | 10.0000 |
Pertsona | 132 | 10 | 1 | 10.0000 |
Elikadura | 102 | 10 | 1 | 10.0000 |
posible | 126 | 9 | 1 | 9.0000 |
jasaten | 108 | 9 | 1 | 9.0000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
or | 593 | 1 | 31 | 0.0323 |
iritziz | 134 | 1 | 13 | 0.0769 |
burua | 318 | 1 | 13 | 0.0769 |
idazkia | 406 | 2 | 22 | 0.0909 |
ditzaten | 99 | 1 | 10 | 0.1000 |
dagokionez | 702 | 5 | 50 | 0.1000 |
berean | 1066 | 3 | 29 | 0.1034 |
denez | 412 | 3 | 29 | 0.1034 |
digu | 236 | 2 | 18 | 0.1111 |
Amaiera | 49 | 1 | 8 | 0.1250 |
dizkion | 50 | 1 | 8 | 0.1250 |
diete | 93 | 1 | 8 | 0.1250 |
Ekonomia | 166 | 1 | 8 | 0.1250 |
zatia | 79 | 1 | 8 | 0.1250 |
Ikasgaia | 118 | 2 | 16 | 0.1250 |
Izenburua | 56 | 1 | 8 | 0.1250 |
datuen | 140 | 1 | 8 | 0.1250 |
arren | 637 | 4 | 32 | 0.1250 |
horretako | 303 | 3 | 23 | 0.1304 |
gero | 1777 | 9 | 68 | 0.1324 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II